n^2+21=4n

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Solution for n^2+21=4n equation: 



n^2+21=4n

We move all terms to the left:

n^2+21-(4n)=0

a = 1; b = -4; c = +21;
Δ = b2-4ac
Δ = -42-4·1·21
Δ = -68
Delta is less than zero, so there is no solution for the equation

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